5x^4-3x^2+1=0

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Solution for 5x^4-3x^2+1=0 equation:


Simplifying
5x4 + -3x2 + 1 = 0

Reorder the terms:
1 + -3x2 + 5x4 = 0

Solving
1 + -3x2 + 5x4 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
0.2 + -0.6x2 + x4 = 0

Move the constant term to the right:

Add '-0.2' to each side of the equation.
0.2 + -0.6x2 + -0.2 + x4 = 0 + -0.2

Reorder the terms:
0.2 + -0.2 + -0.6x2 + x4 = 0 + -0.2

Combine like terms: 0.2 + -0.2 = 0.0
0.0 + -0.6x2 + x4 = 0 + -0.2
-0.6x2 + x4 = 0 + -0.2

Combine like terms: 0 + -0.2 = -0.2
-0.6x2 + x4 = -0.2

The x term is -0.6x2.  Take half its coefficient (-0.3).
Square it (0.09) and add it to both sides.

Add '0.09' to each side of the equation.
-0.6x2 + 0.09 + x4 = -0.2 + 0.09

Reorder the terms:
0.09 + -0.6x2 + x4 = -0.2 + 0.09

Combine like terms: -0.2 + 0.09 = -0.11
0.09 + -0.6x2 + x4 = -0.11

Factor a perfect square on the left side:
(x2 + -0.3)(x2 + -0.3) = -0.11

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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